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-rw-r--r--tex/context/base/mkiv/l-number.lua207
1 files changed, 207 insertions, 0 deletions
diff --git a/tex/context/base/mkiv/l-number.lua b/tex/context/base/mkiv/l-number.lua
new file mode 100644
index 000000000..001ca31f7
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+++ b/tex/context/base/mkiv/l-number.lua
@@ -0,0 +1,207 @@
+if not modules then modules = { } end modules ['l-number'] = {
+ version = 1.001,
+ comment = "companion to luat-lib.mkiv",
+ author = "Hans Hagen, PRAGMA-ADE, Hasselt NL",
+ copyright = "PRAGMA ADE / ConTeXt Development Team",
+ license = "see context related readme files"
+}
+
+-- this module will be replaced when we have the bit library .. the number based sets
+-- might go away
+
+local tostring, tonumber = tostring, tonumber
+local format, floor, match, rep = string.format, math.floor, string.match, string.rep
+local concat, insert = table.concat, table.insert
+local lpegmatch = lpeg.match
+
+number = number or { }
+local number = number
+
+if bit32 then -- I wonder if this is faster
+
+ local btest, bor = bit32.btest, bit32.bor
+
+ function number.bit(p)
+ return 2 ^ (p - 1) -- 1-based indexing
+ end
+
+ number.hasbit = btest
+ number.setbit = bor
+
+ function number.setbit(x,p) -- why not bor?
+ return btest(x,p) and x or x + p
+ end
+
+ function number.clearbit(x,p)
+ return btest(x,p) and x - p or x
+ end
+
+else
+
+ -- http://ricilake.blogspot.com/2007/10/iterating-bits-in-lua.html
+
+ function number.bit(p)
+ return 2 ^ (p - 1) -- 1-based indexing
+ end
+
+ function number.hasbit(x, p) -- typical call: if hasbit(x, bit(3)) then ...
+ return x % (p + p) >= p
+ end
+
+ function number.setbit(x, p)
+ return (x % (p + p) >= p) and x or x + p
+ end
+
+ function number.clearbit(x, p)
+ return (x % (p + p) >= p) and x - p or x
+ end
+
+end
+
+-- print(number.tobitstring(8))
+-- print(number.tobitstring(14))
+-- print(number.tobitstring(66))
+-- print(number.tobitstring(0x00))
+-- print(number.tobitstring(0xFF))
+-- print(number.tobitstring(46260767936,4))
+
+if bit32 then
+
+ local bextract = bit32.extract
+
+ local t = {
+ "0", "0", "0", "0", "0", "0", "0", "0",
+ "0", "0", "0", "0", "0", "0", "0", "0",
+ "0", "0", "0", "0", "0", "0", "0", "0",
+ "0", "0", "0", "0", "0", "0", "0", "0",
+ }
+
+ function number.tobitstring(b,m)
+ -- if really needed we can speed this one up
+ -- because small numbers need less extraction
+ local n = 32
+ for i=0,31 do
+ local v = bextract(b,i)
+ local k = 32 - i
+ if v == 1 then
+ n = k
+ t[k] = "1"
+ else
+ t[k] = "0"
+ end
+ end
+ if m then
+ m = 33 - m * 8
+ if m < 1 then
+ m = 1
+ end
+ return concat(t,"",m)
+ elseif n < 8 then
+ return concat(t)
+ elseif n < 16 then
+ return concat(t,"",9)
+ elseif n < 24 then
+ return concat(t,"",17)
+ else
+ return concat(t,"",25)
+ end
+ end
+
+else
+
+ function number.tobitstring(n,m)
+ if n > 0 then
+ local t = { }
+ while n > 0 do
+ insert(t,1,n % 2 > 0 and 1 or 0)
+ n = floor(n/2)
+ end
+ local nn = 8 - #t % 8
+ if nn > 0 and nn < 8 then
+ for i=1,nn do
+ insert(t,1,0)
+ end
+ end
+ if m then
+ m = m * 8 - #t
+ if m > 0 then
+ insert(t,1,rep("0",m))
+ end
+ end
+ return concat(t)
+ elseif m then
+ rep("00000000",m)
+ else
+ return "00000000"
+ end
+ end
+
+end
+
+function number.valid(str,default)
+ return tonumber(str) or default or nil
+end
+
+function number.toevenhex(n)
+ local s = format("%X",n)
+ if #s % 2 == 0 then
+ return s
+ else
+ return "0" .. s
+ end
+end
+
+-- a,b,c,d,e,f = number.toset(100101)
+--
+-- function number.toset(n)
+-- return match(tostring(n),"(.?)(.?)(.?)(.?)(.?)(.?)(.?)(.?)")
+-- end
+--
+-- -- the lpeg way is slower on 8 digits, but faster on 4 digits, some 7.5%
+-- -- on
+--
+-- for i=1,1000000 do
+-- local a,b,c,d,e,f,g,h = number.toset(12345678)
+-- local a,b,c,d = number.toset(1234)
+-- local a,b,c = number.toset(123)
+-- local a,b,c = number.toset("123")
+-- end
+
+local one = lpeg.C(1-lpeg.S('')/tonumber)^1
+
+function number.toset(n)
+ return lpegmatch(one,tostring(n))
+end
+
+-- function number.bits(n,zero)
+-- local t, i = { }, (zero and 0) or 1
+-- while n > 0 do
+-- local m = n % 2
+-- if m > 0 then
+-- insert(t,1,i)
+-- end
+-- n = floor(n/2)
+-- i = i + 1
+-- end
+-- return t
+-- end
+--
+-- -- a bit faster
+
+local function bits(n,i,...)
+ if n > 0 then
+ local m = n % 2
+ local n = floor(n/2)
+ if m > 0 then
+ return bits(n, i+1, i, ...)
+ else
+ return bits(n, i+1, ...)
+ end
+ else
+ return ...
+ end
+end
+
+function number.bits(n)
+ return { bits(n,1) }
+end